The Normal Distribution

Students learn to compute probabilities for a normally distributed random variable XN(μ,σ2)X \sim N(\mu, \sigma^2) by standardizing to the ZZ-score and using values of the standard normal cumulative distribution function Φ\Phi. The lesson covers left-tail, right-tail, and between-values probabilities.

Step 1 of 119%

Tutorial

The Normal Distribution and Standardization

A continuous random variable XX follows a normal distribution with mean μ\mu and variance σ2\sigma^2, written

XN(μ,σ2),X \sim N(\mu, \sigma^2),

if its density is the bell-shaped curve

f(x)=1σ2πe(xμ)22σ2.f(x) = \dfrac{1}{\sigma\sqrt{2\pi}}\, e^{-\frac{(x-\mu)^2}{2\sigma^2}}.

The curve is symmetric about μ\mu, and the standard deviation σ\sigma controls its spread.

To compute a probability like P(Xa)P(X \le a), we standardize by converting XX to its ZZ-score:

Z=Xμσ    N(0,1).Z = \dfrac{X - \mu}{\sigma} \;\sim\; N(0,1).

This lets us rewrite any normal probability in terms of the standard normal CDF Φ\Phi:

P(Xa)=P ⁣(Zaμσ)=Φ ⁣(aμσ).P(X \le a) = P\!\left(Z \le \dfrac{a-\mu}{\sigma}\right) = \Phi\!\left(\dfrac{a-\mu}{\sigma}\right).

For example, if XN(10,4)X \sim N(10, 4), then σ=4=2\sigma = \sqrt{4} = 2, and

P(X13)=Φ ⁣(13102)=Φ(1.5)=0.9332.P(X \le 13) = \Phi\!\left(\dfrac{13-10}{2}\right) = \Phi(1.5) = 0.9332.

Notice that we always divide by σ\sigma, not σ2\sigma^2.

navigate · Enter open · Esc close · ⌘K/Ctrl K toggle