The Normal Approximation of the Poisson Distribution

When the rate parameter λ\lambda is large, a Poisson distribution can be approximated by a normal distribution with the same mean and variance. This lesson shows how to apply that approximation, using a continuity correction to estimate left-tail, right-tail, and two-sided probabilities.

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Approximating a Poisson by a Normal

If XPoisson(λ),X \sim \text{Poisson}(\lambda), then E[X]=λE[X] = \lambda and Var(X)=λ.\text{Var}(X) = \lambda. For large λ\lambda (a common rule of thumb is λ10\lambda \geq 10), the Poisson distribution is well-approximated by a normal distribution with the same mean and variance:

XPoisson(λ)    approx    N(λ,λ).X \sim \text{Poisson}(\lambda) \;\;\stackrel{\text{approx}}{\sim}\;\; N(\lambda,\,\lambda).

In particular, the standard deviation of the approximating normal is σ=λ.\sigma = \sqrt{\lambda}.

Since Poisson is discrete but the normal is continuous, we apply a continuity correction: shift each boundary by 0.50.5 in the direction that includes more of the distribution. For a left tail P(Xk),P(X \leq k), we shift up to k+0.5:k + 0.5{:}

P(Xk)P(Yk+0.5)=P ⁣(Zk+0.5λλ).P(X \leq k) \approx P(Y \leq k + 0.5) = P\!\left(Z \leq \dfrac{k + 0.5 - \lambda}{\sqrt{\lambda}}\right).

For example, if XPoisson(25),X \sim \text{Poisson}(25), then μ=25\mu = 25 and σ=5,\sigma = 5, so

P(X30)P ⁣(Z30.5255)=P(Z1.10)0.8643.P(X \leq 30) \approx P\!\left(Z \leq \dfrac{30.5 - 25}{5}\right) = P(Z \leq 1.10) \approx 0.8643.
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