The Distribution Function Method

Find the distribution of a transformed continuous random variable Y=g(X)Y=g(X) by computing FY(y)=P(g(X)y)F_Y(y) = P(g(X)\le y) directly from the CDF of XX, then differentiating to recover the pdf.

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Tutorial

The Distribution Function Method

The distribution function method finds the distribution of Y=g(X)Y = g(X) by working directly from the definition of the CDF:

FY(y)=P(Yy)=P(g(X)y).F_Y(y) = P(Y \le y) = P(g(X) \le y).

The procedure has three steps:

  1. Rewrite the event {g(X)y}\{g(X) \le y\} as an equivalent event involving XX alone.
  2. Evaluate the resulting probability using FXF_X.
  3. Differentiate to recover the pdf: fY(y)=FY(y)f_Y(y) = F_Y'(y).

To illustrate, let XU(0,1)X \sim U(0, 1) so FX(x)=xF_X(x) = x on [0,1][0,1], and let Y=X3Y = X^3. Since g(x)=x3g(x) = x^3 is increasing on this interval,

FY(y)=P(X3y)=P(Xy1/3)=FX(y1/3)=y1/3,0y1.F_Y(y) = P(X^3 \le y) = P(X \le y^{1/3}) = F_X(y^{1/3}) = y^{1/3}, \quad 0 \le y \le 1.

Differentiating,

fY(y)=13y2/3,0<y1.f_Y(y) = \dfrac{1}{3}\, y^{-2/3}, \quad 0 < y \le 1.
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