The Poisson Approximation of the Binomial Distribution

When the number of trials is large and the success probability is small, the binomial distribution can be approximated by a Poisson distribution with parameter λ=np\lambda = np. This lesson develops the approximation formula, applies it to concrete word problems, and extends it to cumulative probabilities such as P(Xk)P(X \geq k) and P(Xk)P(X \leq k).

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Approximating the Binomial With a Poisson

The binomial pmf P(X=k)=(nk)pk(1p)nkP(X=k) = \binom{n}{k}p^k(1-p)^{n-k} is unwieldy to compute by hand when nn is large. When pp is also small, the Poisson approximation provides a clean alternative.

Poisson Approximation to the Binomial. If XBinomial(n,p)X \sim \mathrm{Binomial}(n,p) with nn large and pp small, then

P(X=k)    eλλkk!,where λ=np.P(X = k) \;\approx\; \dfrac{e^{-\lambda}\, \lambda^k}{k!}, \qquad \text{where } \lambda = np.

Notice that both distributions share the same mean (np=λnp = \lambda). As nn \to \infty and p0p \to 0 with λ=np\lambda = np held fixed, the binomial pmf converges to the Poisson pmf. A common rule of thumb is n20n \geq 20 and p0.05p \leq 0.05.

Illustration. Let XBinomial(100,0.03)X \sim \mathrm{Binomial}(100, 0.03). Setting λ=np=3:\lambda = np = 3{:}

P(X=1)    e3311!=3e30.149.P(X = 1) \;\approx\; \dfrac{e^{-3} \cdot 3^1}{1!} = 3e^{-3} \approx 0.149.

The exact binomial probability is 0.147,0.147, so the approximation is accurate to three decimal places.

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